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3.
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Identify the coordinates of the vertex and focus, the equations of the axis of
symmetry and directrix, and the direction of opening of the parabola with the equation  . Then find the length of the latus rectum and graph the parabola.
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4.
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Identify the coordinates of the vertex and focus, the equations of the axis of
symmetry and directrix, and the direction of opening of the parabola with the equation y =
6x2 + 24x + 18. Then find the length of the latus rectum and graph the
parabola.
a. | The coordinates of the vertex and focus are (2, –6) and (2,  )
respectively.
The equations of the axis of symmetry and directrix are  and y =
 respectively.
The direction of the opening
is upward, and the length of the latus rectum is  units.
Thus, the graph of
the parabola is as follows:
 | c. | The coordinates of the vertex and
focus are (2, –6) and (2,  ) respectively.
The equations of the axis of
symmetry and directrix are  and y = 
respectively.
The direction of opening is downward, and the length of the latus rectum is  units.
Thus, the graph of the parabola is as follows:
 | b. | The coordinates of the vertex and focus are (–2, –6) and (–2,  ) respectively.
The equations of the axis of symmetry and directrix are y =
–6 and y =  respectively.
The direction of opening is
upward, and the length of the latus rectum is  units. Thus, the graph of the
parabola is as follows:
 | d. | The coordinates of the vertex and focus are
(–2, –6) and (–2,  ) respectively. The equations of the axis of
symmetry and directrix are  and y = 
respectively.
The direction of opening is upward, and the length of the latus rectum is  units. Thus, the graph of the parabola is as follows:
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